Hello coders, today we will be solving Collections.Counter() in Python Hacker Rank Solution.
Objective
A counter is a container that stores elements as dictionary keys, and their counts are stored as dictionary values.
Sample Code
>>> from collections import Counter >>> >>> myList = [1,1,2,3,4,5,3,2,3,4,2,1,2,3] >>> print Counter(myList) Counter({2: 4, 3: 4, 1: 3, 4: 2, 5: 1}) >>> >>> print Counter(myList).items() [(1, 3), (2, 4), (3, 4), (4, 2), (5, 1)] >>> >>> print Counter(myList).keys() [1, 2, 3, 4, 5] >>> >>> print Counter(myList).values() [3, 4, 4, 2, 1]
Task
Raghu is a shoe shop owner. His shop has X number of shoes.
He has a list containing the size of each shoe he has in his shop.
There are N number of customers who are willing to pay xi amount of money only if they get the shoe of their desired size.
Your task is to compute how much money Raghu earned.
Input Format
The first line contains X, the number of shoes.
The second line contains the space separated list of all the shoe sizes in the shop.
The third line contains N, the number of customers.
The next N lines contain the space separated values of the shoe size desired by the customer and xi, the price of the shoe.
Constraints
0 < X < 10^3
0 < N <= 10^3
20 < xi < 100
2 < shoe size < 20
Output Format
Print the amount of money earned by Raghu.
Sample Input
10 2 3 4 5 6 8 7 6 5 18 6 6 55 6 45 6 55 4 40 18 60 10 50
Sample Output
200
Explanation
Customer 1: Purchased size 6 shoe for $55.
Customer 2: Purchased size 6 shoe for $45.
Customer 3: Size 6 no longer available, so no purchase.
Customer 4: Purchased size 4 shoe for $40.
Customer 5: Purchased size 18 shoe for $60.
Customer 6: Size 10 not available, so no purchase.
Total money earned = 55 + 45 + 40 + 60 = $200
Solution - Collections.Counter() Hacker Rank Solution in Python
Python 3
# Enter your code here. Read input from STDIN. Print output to STDOUT from collections import Counter numShoes = int(input()) shoes = Counter(map(int, input().split())) numCust = int(input()) income = 0 for i in range(numCust): size, price = map(int, input().split()) if shoes[size]: income += price shoes[size] -= 1 print(income)
Disclaimer: The above Problem (Collections.Counter() in Python) is generated by Hacker Rank but the Solution is provided by Sloth Coders.
Happy Coding !!
A Sloth Who loves to Code
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