Printing Pattern Using Loops in C - HackerRank Solution

Hello coders, today we will be solving Printing Pattern Using Loops in C HackerRank Solution.

Task

Print a pattern of numbers from 1 to n as shown below. Each of the numbers is separated by a single space.

4 4 4 4 4 4 4  
4 3 3 3 3 3 4   
4 3 2 2 2 3 4   
4 3 2 1 2 3 4   
4 3 2 2 2 3 4   
4 3 3 3 3 3 4   
4 4 4 4 4 4 4   

Input Format

The input will contain a single integer n.

Constraints

1 ≤ n ≤ 1000

Sample Input 0

2

Sample Output 0

2 2 2
2 1 2
2 2 2

Sample Input 1

5

Sample Output 1

5 5 5 5 5 5 5 5 5 
5 4 4 4 4 4 4 4 5 
5 4 3 3 3 3 3 4 5 
5 4 3 2 2 2 3 4 5 
5 4 3 2 1 2 3 4 5 
5 4 3 2 2 2 3 4 5 
5 4 3 3 3 3 3 4 5 
5 4 4 4 4 4 4 4 5 
5 5 5 5 5 5 5 5 5

Sample Input 2

7

Sample Output 2

7 7 7 7 7 7 7 7 7 7 7 7 7 
7 6 6 6 6 6 6 6 6 6 6 6 7 
7 6 5 5 5 5 5 5 5 5 5 6 7 
7 6 5 4 4 4 4 4 4 4 5 6 7 
7 6 5 4 3 3 3 3 3 4 5 6 7 
7 6 5 4 3 2 2 2 3 4 5 6 7 
7 6 5 4 3 2 1 2 3 4 5 6 7 
7 6 5 4 3 2 2 2 3 4 5 6 7 
7 6 5 4 3 3 3 3 3 4 5 6 7 
7 6 5 4 4 4 4 4 4 4 5 6 7 
7 6 5 5 5 5 5 5 5 5 5 6 7 
7 6 6 6 6 6 6 6 6 6 6 6 7 
7 7 7 7 7 7 7 7 7 7 7 7 7 

Solution - Printing Pattern Using Loops in C - Hacker Rank Solution 

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
int main()
{
    int i,j,k,m,n,x;
    scanf("%d",&n);
    k=n;
    m = n+(n-1);
    for(i=0;i<m;i++)
    {
        for(j=0;j<m;j++)
        {
            if(i<=n-1)
            {        
                if(i==0)
                {
                printf("%d ",k);
                }
                if(i>=1)
                {
                    if(j<i)
                    {
                        printf("%d ",k-j);
                    }
                    else if(j>=i && j<m-i)
                    {
                        printf("%d ",k-i);
                    }
                    else 
                    {
                        printf("%d ",(j-k+1)+1);
                    }
                }
            }
            else if(i==n-1)
            {
                if(j<n)
                {
                    printf("%d ",k-j);
                }
                else
                {
                    printf("%d ",(j-k+1)+1);
                }
            }
            else if(i>=n)
            {
                x = m-i-1;
                if(i==m)
                {
                printf("%d ",k);
                }
                if(j<x)
                {
                    printf("%d ",k-j);
                }
                else if(j>=x && j<m-x)
                {
                    printf("%d ",k-x);
                }
                else 
                {
                    printf("%d ",(j-k+1)+1);
                }    
            }
        }
        printf("\n");
    }
}

Disclaimer: The above Problem (Printing Pattern Using Loops in C) is generated by Hacker Rank but the Solution is provided by Sloth Coders.

A Sloth Who Code 

Sloth Coders 

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