Pointers in C Hackerrank Solution

Pointers in C Hacker Rank Solution

Today we will be solving Pointers in C Hacker Rank Solution.

Objective

In this challenge, you will learn to implement the basic functionalities of pointers in C. A pointer in C is a way to share a memory address among different contexts (primarily functions). They are primarily used whenever a function needs to modify the content of a variable that it does not own.

In order to access the memory address of a variable, val , prepend it with & sign. For example, &val returns the memory address of val .

This memory address is assigned to a pointer and can be shared among various functions. For example, int*p = &val will assign the memory address of val to pointer p. To access the content of the memory to which the pointer points, prepend it with a *. For example, *p will return the value reflected by val and any modification to it will be reflected at the source (val).

void increment(int *v) {
        (*v)++; 
    }
      	int main() {
        int a;
        scanf("%d", &a);
        increment(&a);
        printf("%d", a);
    	return 0;      
    }

Task

Complete the function void update(int *a,int *b). It receives two integer pointers, int* a and int* b. Set the value of a to their sum, and b to their absolute difference. There is no return value, and no return statement is needed.

a' = a+b
b' = |a-b|

Input Format

The input will contain two integers, a and b, separated by a newline.

Output Format

Modify the two values in place and the code stub main() will print their values.

Note: Input/output will be automatically handled. You only have to complete the function described in the 'task' section.

Sample Input

4
5

Sample Output

9
1

Explanation

a' = 4 + 5 = 9
b' = |4 - 5| = 1

Solution - Pointers in C Hacker Rank Solution

#include <stdio.h>

void update(int *a,int *b) {
    // Complete this function  
    int x, y;
    x = *a + *b;
    y = *a - *b;
    *a = x;
    *b = abs(y);  
}

int main() {
    int a, b;
    int *pa = &a, *pb = &b;
    
    scanf("%d %d", &a, &b);
    update(pa, pb);
    printf("%d\n%d", a, b);

    return 0;
}

Pointers in C Hackerrank Solution

Disclaimer: The above problem (Pointers in C) is generated by Hacker Rank but the Solution is provided by Sloth Coders.

Sloth Coders

Search Suggest

Pointers in C Hackerrank Solution