Array Reversal in C - HackerRank Solution

Hello coders, today we will be solving Array Reversal in C Hacker Rank Solution.

Task 

Given an array, of size n, reverse it.

Example: If array, arr = [1, 2, 3, 4, 5], after reversing it, the array should be, arr = [5, 4, 3, 2, 1] .

Input Format

The first line contains an integer, n, denoting the size of the array. The next line contains n space-separated integers denoting the elements of the array.

Constraints

1  ≤ n ≤ 1000

1  ≤ arri  ≤ 1000, where arri is the ith element of the array.

Output Format 

The output is handled by the code given in the editor, which would print the array.

Sample Input 0

6
16 13 7 2 1 12 

Sample Output 0

12 1 2 7 13 16

Explanation 0

Given array, arr = [16, 17, 7, 2, 1, 12]. After reversing the array, arr = [12, 1, 2, 7, 17, 16]

Sample Input 1

7
1 13 15 20 12 13 2 

Sample Output 1

2 13 12 20 15 13 1 

Sample Input 2

8
15 5 16 15 17 11 5 11 

Sample Output 2

11 5 11 17 15 16 5 15 

Solution - Array Reversal in C - Hacker Rank Solution 

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int num, *arr, i;
    scanf("%d", &num);
    arr = (int*) malloc(num * sizeof(int));
    for(i = 0; i < num; i++) {
        scanf("%d", arr + i);
    }
    /* Write the logic to reverse the array. */ 
    int* left_ptr = arr;
    int* right_ptr;
    int temp;
    for(i = 0; i < num; i++) {
        if(i == num - 1) {
            right_ptr = (arr + i);
        }
    }
    while(left_ptr < right_ptr) {
        temp = *right_ptr;
        *right_ptr = *left_ptr;
        *left_ptr = temp;
        right_ptr--;
        left_ptr++;
    }
      
    for(i = 0; i < num; i++) {
        printf("%d ", *(arr + i));
    }
    free(arr);
    return 0;
}

Disclaimer: The above Problem (Array Reversal in C) is generated by Hacker Rank but the Solution is provide by Sloth Coders.

A Sloth Who Code 

Sloth Coders

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