Strings in C++ | HackerRank Solution

Hello there, today we are going to solve Strings Hacker Rank Solution in C++.

Table Of Contents 👊

• Objective
• Input Format 
• Output Format
• Solution

Objective

C++ provides a nice alternative data type to manipulate strings, and the data type is conveniently called string. Some of its widely used features are the following:

Declaration

string a = "abc";

Size

int len = a.size();

Concatenate two strings:

string a = "abc";
string b = "def";
string c = a + b; // c = "abcdef".

Accessing ith element:

string s = "abc";
char   c0 = s[0];   // c0 = 'a'
char   c1 = s[1];   // c1 = 'b'
char   c2 = s[2];   // c2 = 'c'

s[0] = 'z';         // s = "zbc"

P.S.: We will use cin/cout to read/write a string.

Input Format

You are given two strings, a and b, separated by a new line. Each string will consist of lower case Latin characters ('a'-'z').

Output Format

In the first line print two space-separated integers, representing the length of a and b respectively.

In the second line print the string produced by concatenating a and b (a+b).

In the third line print two strings separated by a space, a’ and b’. a’ and b’ are the same as a and b, respectively, except that their first characters are swapped.

Sample Input

abcd
ef

Sample Output

4 2
abcdef
ebcd af

Explanation

• a = "abcd"
• b = "ef"
• |a| = 4
• |b| = 2
• a + b = "abcdef"
• a’ = "ebcd"
• b’ = "af"

Solution - Strings in C++

#include <iostream>
#include <string>
using namespace std;

int main() {
    // Complete the program
    string a,b;
    cin >> a >> b ;
    int l_of_a = a.size();
    int l_of_b = b.size();
    cout << l_of_a <<" "<<l_of_b << endl;
    cout << a << b << endl;
    char c1 = a[0];
    char c2 = b[0];
    a[0] = c2;
    b[0] = c1;
    cout << a <<" "<<b;
    return 0;
}

Disclaimer: The above Problem (Strings) is generated by Hacker Rank but the Solution is Provided by Sloth Coders. This tutorial is only for Educational and Learning Purpose.