Hello coders, today we are going to solve Symmetric Difference Hacker Rank Solution.
Objective
Today, we're learning about a new data type: sets.
Concept
If the inputs are given on one line separated by a character (the delimiter), use split() to get the separate values in the form of a list. The delimiter is space (ascii 32) by default. To specify that comma is the delimiter, use string.split(','). For this challenge, and in general on HackerRank, space will be the delimiter.
Usage:
>> a = raw_input()
5 4 3 2
>> lis = a.split()
>> print (lis)
['5', '4', '3', '2']
If the list values are all integer types, use the map() method to convert all the strings to integers.
>> newlis = list(map(int, lis))
>> print (newlis)
[5, 4, 3, 2]
Sets are an unordered collection of unique values. A single set contains values of any immutable data type.
Creating Sets
>> myset = {1, 2} # Directly assigning values to a set
>> myset = set() # Initializing a set
>> myset = set(['a', 'b']) # Creating a set from a list
>> myset
{'a', 'b'}
MODIFYING SETS
Using the add() function:
>> myset.add('c') >> myset {'a', 'c', 'b'} >> myset.add('a') # As 'a' already exists in the set, nothing happens >> myset.add((5, 4)) >> myset {'a', 'c', 'b', (5, 4)}
Using the update() function:
>> myset.update([1, 2, 3, 4]) # update() only works for iterable objects
>> myset
{'a', 1, 'c', 'b', 4, 2, (5, 4), 3}
>> myset.update({1, 7, 8})
>> myset
{'a', 1, 'c', 'b', 4, 7, 8, 2, (5, 4), 3}
>> myset.update({1, 6}, [5, 13])
>> myset
{'a', 1, 'c', 'b', 4, 5, 6, 7, 8, 2, (5, 4), 13, 3}
REMOVING ITEMS
Both the discard() and remove() functions take a single value as an argument and removes that value from the set. If that value is not present, discard() does nothing, but remove() will raise a KeyError exception.
>> myset.discard(10)
>> myset
{'a', 1, 'c', 'b', 4, 5, 7, 8, 2, 12, (5, 4), 13, 11, 3}
>> myset.remove(13)
>> myset
{'a', 1, 'c', 'b', 4, 5, 7, 8, 2, 12, (5, 4), 11, 3}
COMMON SET OPERATIONS Using union(), intersection() and difference() functions.
>> a = {2, 4, 5, 9}
>> b = {2, 4, 11, 12}
>> a.union(b) # Values which exist in a or b
{2, 4, 5, 9, 11, 12}
>> a.intersection(b) # Values which exist in a and b
{2, 4}
>> a.difference(b) # Values which exist in a but not in b
{9, 5}
The union() and intersection() functions are symmetric methods:
>> a.union(b) == b.union(a)
True
>> a.intersection(b) == b.intersection(a)
True
>> a.difference(b) == b.difference(a)
False
Task
Given 2 sets of integers, M and N, print their symmetric difference in ascending order. The term symmetric difference indicates those values that exist in either M or N but do not exist in both.
Input Format
The first line of input contains an integer, M.
The second line contains M space-separated integers.
The third line contains an integer, N.
The fourth line contains N space-separated integers.
Output Format
Output the symmetric difference integers in ascending order, one per line.
Sample Input
STDIN Function
----- --------
4 set a size M = 4
2 4 5 9 a = {2, 4, 5, 9}
4 set b size N = 4
2 4 11 12 b = {2, 4, 11, 12}
Sample Output
5
9
11
12
Solution - Symmetric Difference - Hacker Rank Solution
Python 3
# Enter your code here. Read input from STDIN. Print output to STDOUT
if __name__ == "__main__":
M = int(input().strip())
set_m = set(map(int, input().strip().split(' ')))
N = int(input().strip())
set_n = set(map(int, input().strip().split(' ')))
for j in sorted(set_m ^ set_n):
print(j)
Disclaimer: The above Problem (Symmetric Difference) is generated by Hacker Rank but the Solution is provided by Sloth Coders. This tutorial is only for Educational and Learning Purpose.
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