What's up coders, today we are going to solve String Formatting in Python Hacker Rank Solution.
Problem
Given an integer, n, print the following values for each integer i from 1 to n:
- Decimal
- Octal
- Hexadecimal (capitalized)
- Binary
The four values must be printed on a single line in the order specified above for each i from 1 to n. Each value should be space-padded to match the width of the binary value of n.
Input Format
A single integer denoting n.
Constraints
- 1 <= n <= 99
Output Format
Print n lines where each line i (in the range 1 <= i <= n ) contains the respective decimal, octal, capitalized hexadecimal, and binary values of i. Each printed value must be formatted to the width of the binary value of n.
Sample Input
17
Sample Output
1 1 1 1 2 2 2 10 3 3 3 11 4 4 4 100 5 5 5 101 6 6 6 110 7 7 7 111 8 10 8 1000 9 11 9 1001 10 12 A 1010 11 13 B 1011 12 14 C 1100 13 15 D 1101 14 16 E 1110 15 17 F 1111 16 20 10 10000 17 21 11 10001
Solution - String Formatting in Python - Hacker Rank Solution
def print_formatted(number): # your code goes here width = len(bin(number)[2:]) for i in range(1, number+1): deci = str(i) octa = oct(i)[2:] hexa = hex(i)[2:].upper() bina = bin(i)[2:] print(deci.rjust(width),octa.rjust(width),hexa.rjust(width),bina.rjust(width)) if __name__ == '__main__': n = int(input()) print_formatted(n)
Disclaimer: The above Problem (String Formatting in Python) is generated by Hacker Rank but the Solution is provided by Sloth Coders.
Happy Coding !!
A Sloth Who loves to Code
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