Conditional Statements in C++ - Hacker Rank Solution
Today we are going to learn about Conditional Statements in C++ which is one of the main components of C++. It is widely used in a lot of programs ranging from simplest programs to complex problems.
So, It is very necessary to learn about this. We will learning this by solving one of the easiest HackerRank problem.
After solving this problem, you will Completely understand about this topic and will be able to solve this kind of problem by yourself.
So, without further ado let's dive into this problem.
Contents
Problem
If and else are two of the most frequently used conditionals in C/C++, and they enable you to execute zero or one conditional statement among many such dependent conditional statements. We use them in the following ways:
1. if: This executes the body of bracketed code starting with statement1 if condition evaluates to true.
if (condition) {
statement1;
. . .
}
2. if - else: This executes the body of a bracketed code starting with statement1 if condition evaluates to true, or it executes the body of code starting with statement2 if condition evaluates to false. Note that only one of the bracketed code sections will be executed.
if (condition) { statement1; . . . } else { statement2; . . . }
3. if - else if - else: In this structure, dependent statements are chained together and the condition for each statement is only checked if all prior conditions in the chain evaluated to false. Once a condition evaluates to true, the bracketed code associated with that statement is executed and the program then skips to the end of the chain of statements and continues executing. If each condition in the chain evaluates to false, then the body of bracketed code in the else block at the end is executed.
if ( first condition) { . . . } else if (second condition) { . . . } . . . else if ((n-1)'th condition) { . . . } else { . . . }
Given an integer n, do the following:
- If 1 ≤ n ≤ 9, print the lowercase English word corresponding to the number (e.g. one for 1, two for 2, etc.).
- If n > 9, print Greater than 9.
Input Format
A single integer, n.
Constrains
- 1 ≤ n ≤ 109
Output Format
If 1 ≤ n ≤ 9, then print the lowercase English word corresponding to the number (e.g. one for 1, two for 2, etc.); Otherwise , Print Greater than 9.
Sample Input 0
5
Sample Output 0
five
Explanation 0
five is the English word for the number 5.
Sample Input 1
8
Sample Output 1
eight
Explanation 1
eight is the English word for the number 8.
Sample Input 2
44
Sample Output 2
Greater than 9
Explanation 2
n = 44 is greater than 9, so we print Greater than 9.
Solution - Conditional Statements in C++
#include <bits/stdc++.h> using namespace std; int main() { int n; cin >> n; cin.ignore(numeric_limits<streamsize>::max(), '\n'); // Write Your Code Here if ( n == 1){ cout << "one"; } else if (n == 2){ cout << "two"; } else if (n == 3){ cout << "three"; } else if (n == 4){ cout << "four"; } else if (n == 5){ cout << "five"; } else if (n == 6){ cout << "six"; } else if (n == 7){ cout << "seven"; } else if (n == 8){ cout << "eight"; } else if (n == 9){ cout << "nine"; } else{ cout << "Greater than 9"; } return 0; }
Conditional Statements in C++ - Solution |
Conditional Statements in C++ - Solution |
Conditional Statements in C++ - Result |
Explanation
Here in the given code we have used three statements: if statements, if - else statement and else statement.
When the input lies between 1 to 9, the output will show same numbers in English format. And when the input is more than 9, it will show Greater than 9.
Conclusion
So, coders today we have learned about if and else statements which mainly includes if , if - else and else statements. The following problem is generated by Hacker Rank but the solution is provided by Sloth Coders.
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