# Python Finding the Percentage - Hacker Rank Solution

## Finding The Percentage - Hacker Rank Solution

Hello coders, today we are going to solve Python Finding The Percentage Hacker Rank Solution.

The provided code stub read in a dictionary containing key/value pairs of name:[Marks] for a list of students. Print the average of the marks array for the student name provided, showing 2 places after the decimal.

## Example

marks key: value pairs are

'alpha':[20, 30, 40]

'beta':[30, 50, 70]

query_name = 'beta'

The query_name is 'beta'. beta's average score is (30 + 50 + 70)/3 = 50.0.

## Input Format

The first line contains the integer n, the number of students's records. The next n lines contain the names and marks obtained by a student, each value separated by a space. The final line contains query_name , the name of a student to query.

## Constrains

• 2 ≤ n ≤ 10
• 0 ≤ marks[i] ≤ 100
• length of the marks array = 3

## Output Format

Print one line: The average of the marks obtained by the particular student correct to 2 decimal places.

```3
Krishna 67 68 69
Arjun 70 98 63
Malika 52 56 60
Malika```

```56.00
```

## Explanation 0

Marks of Malika are {52, 56, 60} whose average is (52 +56 +60)/3 ⇒  56

```2
Harsh 25 26.5 28
Anurag 26 28 30
Harsh
```

```26.50
```

## Python 3

```if __name__ == '__main__':
n = int(input())
student_marks = {}
for _ in range(n):
name, *line = input().split()
scores = list(map(float, line))
student_marks[name] = scores
query_name = input()
#finding the percentage in python - Hacker Rank Solution
output = list(student_marks[query_name])
per = sum(output)/len(output);
print("%.2f" % per);
```

 Finding The Percentage in Python - Hacker Rank Solution

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